document.write( "Question 179567: i need some help because im having trouble with this problem\r
\n" ); document.write( "\n" ); document.write( "4x^2=36 \r
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Algebra.Com's Answer #134509 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"4x%5E2=36\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=%2836%29%2F%284%29\" Divide both sides by \"4\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=9\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"x=0%2B-sqrt%289%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%289%29\" or \"x=-sqrt%289%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"x=3\" or \"x=-3\" Take the square root of \"9\" to get \"3\".\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=3\" or \"x=-3\".
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