document.write( "Question 179541: in four years time a mother will be three times old as her son. four years ago she was five times as old as her son. find their present age \n" ); document.write( "
Algebra.Com's Answer #134486 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Let \n" ); document.write( "In 4 years, the Mother's age will be \n" ); document.write( "In 4 years, the Son age will be \n" ); document.write( "4 years ago, the Mother's age was \n" ); document.write( "4 years ago, the Son's age was \n" ); document.write( "given: \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "----------------------- \n" ); document.write( "There are 2 equations and 2 unknowns, so it's solvable \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "Now subtract (1) from (2) \n" ); document.write( "(2) \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Substitute this in (2) \n" ); document.write( "(2) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The Mother is 44 and the Son is 12 \n" ); document.write( "check: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |