document.write( "Question 179541: in four years time a mother will be three times old as her son. four years ago she was five times as old as her son. find their present age \n" ); document.write( "
Algebra.Com's Answer #134486 by josmiceli(19441)\"\" \"About 
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Let \"m\"= the Mother's age now
\n" ); document.write( "Let \"s\"= her Son's age now
\n" ); document.write( "In 4 years, the Mother's age will be \"m+%2B+4\"
\n" ); document.write( "In 4 years, the Son age will be \"s+%2B+4\"
\n" ); document.write( "4 years ago, the Mother's age was \"m+-+4\"
\n" ); document.write( "4 years ago, the Son's age was \"s+-+4\"
\n" ); document.write( "given:
\n" ); document.write( "(1) \"m+%2B+4+=+3%2A%28s+%2B+4%29\"
\n" ); document.write( "(2) \"m+-+4+=+5%2A%28s+-+4%29\"
\n" ); document.write( "-----------------------
\n" ); document.write( "There are 2 equations and 2 unknowns, so it's solvable
\n" ); document.write( "(1) \"m+%2B+4+=+3s+%2B+12\"
\n" ); document.write( "(2) \"m+-+4+=+5s+-+20\"
\n" ); document.write( "Now subtract (1) from (2)
\n" ); document.write( "(2) \"m+-+4+=+5s+-+20\"
\n" ); document.write( "(1) \"-m+-+4+=+-3s+-+12\"
\n" ); document.write( "\"-8+=+2s+-+32\"
\n" ); document.write( "\"2s+=+24\"
\n" ); document.write( "\"s+=+12\"
\n" ); document.write( "Substitute this in (2)
\n" ); document.write( "(2) \"m+-+4+=+5%2A12+-+20\"
\n" ); document.write( "\"m+-+4+=+60+-+20\"
\n" ); document.write( "\"m+-+4+=+40\"
\n" ); document.write( "\"m+=+44\"
\n" ); document.write( "The Mother is 44 and the Son is 12
\n" ); document.write( "check:
\n" ); document.write( "(1) \"m+%2B+4+=+3%2A%28s+%2B+4%29\"
\n" ); document.write( "(1) \"44+%2B+4+=+3%2A%2812+%2B+4%29\"
\n" ); document.write( "\"48+=+48\"
\n" ); document.write( "(2) \"m+-+4+=+5%2A%28s+-+4%29\"
\n" ); document.write( "(2) \"44+-+4+=+5%2A%2812+-+4%29\"
\n" ); document.write( "\"40+=+40\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );