document.write( "Question 179530This question is from textbook Elementary and Intermediate Algebra
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document.write( ": An investment of $10,000 in the Emerging Country Debt Fund in 2001 was worth $24,780 in 2006. Use the formula to find the 5 year average annual return. The formula is r=(S/P)^1/n-1. I am totally lost with this word problem. Could somebody help?Thank you in advance. \n" );
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Algebra.Com's Answer #134477 by stanbon(75887) ![]() You can put this solution on YOUR website! An investment of $10,000 in the Emerging Country Debt Fund in 2001 was worth $24,780 in 2006. Use the formula to find the 5 year average annual return. The formula is r=(S/P)^1/n-1. I am totally lost with this word problem. \n" ); document.write( "---------------- \n" ); document.write( "P=initial investment = 10,000 ; n=number of years = 5 ; and the amount S \n" ); document.write( "that it is worth after n years = 24,780 \n" ); document.write( " \n" ); document.write( "----------------------- \n" ); document.write( "r=(S/P)^[1/(n-1)] \n" ); document.write( "--- \n" ); document.write( "Since S=24,780 and P=10,000, you get\r \n" ); document.write( "\n" ); document.write( "r = (24,780/10,000)^(1/(5-1)] = 1.2546 = 125%\r \n" ); document.write( "\n" ); document.write( "Comment: The \"1\" might refer to the investment at the beginning of each year; \n" ); document.write( "then the 0.25 would be the interest rate. \n" ); document.write( "For example 10,000*(1+0.2546)^4 = $24,775 \n" ); document.write( "This would be the value after 4 years if 10,000 was compounded yearly \n" ); document.write( "at 25% \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------------------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |