document.write( "Question 179525This question is from textbook Algebra 2 an integrated approach
\n" ); document.write( ": I tried to solve this on my own but i don't understand how i would even go about correctly starting it.\r
\n" ); document.write( "\n" ); document.write( "6x/x+4=2x+2/x-1 \n" ); document.write( "
Algebra.Com's Answer #134473 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
6x/(x+4) = (2x+2)/(x-1))\r
\n" ); document.write( "\n" ); document.write( "Cross multiply to get:\r
\n" ); document.write( "\n" ); document.write( "6x(x-1) = (x+4)(2x+2)\r
\n" ); document.write( "\n" ); document.write( "Simplify:\r
\n" ); document.write( "\n" ); document.write( "6x^2 - 6x = 2x^2 +10x + 8\r
\n" ); document.write( "\n" ); document.write( "4x^2 - 16x - 8 = 0\r
\n" ); document.write( "\n" ); document.write( "x^2 - 4x -2 = 0\r
\n" ); document.write( "\n" ); document.write( "x = [4 +- sqrt(16 - 4*1*-2)]/2\r
\n" ); document.write( "\n" ); document.write( "x = [4 +- sqrt(24)]/2\r
\n" ); document.write( "\n" ); document.write( "x = [4 +- 2sqrt(6)]/2\r
\n" ); document.write( "\n" ); document.write( "x = [2 +- sqrt(6)]
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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