document.write( "Question 179507: How can $42,000 be invested, part 11% annual simple interest and the remainder at 6% annual simple interest, so that the interest earned by the two accounts will be equal? \n" ); document.write( "
Algebra.Com's Answer #134457 by ankor@dixie-net.com(22740)\"\" \"About 
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How can $42,000 be invested, part 11% annual simple interest and the remainder
\n" ); document.write( " at 6% annual simple interest, so that the interest earned by the two accounts will be equal?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt invested at 11%
\n" ); document.write( "then
\n" ); document.write( "(42000-x) = amt invested at 6%
\n" ); document.write( ":
\n" ); document.write( "11% interest = 6% interest
\n" ); document.write( ".11x = .06(42000-x)
\n" ); document.write( ".11x = 2520 - .06x
\n" ); document.write( ".11x + .06x = 2520
\n" ); document.write( "x = \"2520%2F.17\"
\n" ); document.write( "x = $14,823.53 invested at 11%
\n" ); document.write( "then
\n" ); document.write( "42000 - 14823.53 = $27,176.47 invested at 6%
\n" ); document.write( ":
\n" ); document.write( ";
\n" ); document.write( "Check solution by finding the interest on both
\n" ); document.write( ".11 * 14823.53 = 1630.59
\n" ); document.write( ".06 * 27176.47 = 1630.59; confirms our solutions
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