document.write( "Question 179488: i don't understand how to do this: please help: its a worksheet
\n" ); document.write( "a rectangle is 12 cm longer than it is wide. if its length and width are both decreased by 2 cm its area is decreased by 108 cm. squared. find its original dementions.
\n" ); document.write( "

Algebra.Com's Answer #134426 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let L=original length, W=original width, and A=original area of the rectangle\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"a rectangle is 12 cm longer than it is wide.\" translates to \"L=W%2B12\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "and \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"if its length and width are both decreased by 2 cm its area is decreased by 108 cm\" means that the new area is \"A-108=%28L-2%29%28W-2%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Note: the original area of the rectangle is \"A=LW\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"A-108=%28L-2%29%28W-2%29\" Start with the second equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"LW-108=%28L-2%29%28W-2%29\" Plug in \"A=LW\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28W%2B12%29W-108=%28W%2B12-2%29%28W-2%29\" Plug in \"L=W%2B12\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"W%28W%2B12%29-108=%28W%2B12-2%29%28W-2%29\" Rearrange the terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"W%28W%2B12%29-108=%28W%2B10%29%28W-2%29\" Combine like terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"W%28W%2B12%29-108=W%5E2%2B8W-20\" FOIL\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"W%5E2%2B12W-108=W%5E2%2B8W-20\" Distribute\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4W=88\" Subtract \"W%5E2\" from both sides. Subtract \"8W\" from both sides. Add 108 to both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"W=88%2F4\" Divide both sides by 4 to isolate W.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"W=22\" Divide. So the original width of the rectangle is 22 cm\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"L=W%2B12\" Go back to the first equation\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"L=22%2B12\" Plug in \"W=22\" \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"L=34\" Add. So the original length of the rectangle is 34 cm\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "================================================================\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the original dimensions of the rectangle are:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Length: 34 cm
\n" ); document.write( "Width: 22 cm\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );