document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=179488>Question 179488</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i don't understand how to do this: please help: its a worksheet<BR>\n" );
document.write( "a rectangle is 12 cm longer than it is wide. if its length and width are both decreased by 2 cm its area is decreased by 108 cm. squared. find its original dementions.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #134425 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=134425\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a rectangle is 12 cm longer than it is wide. if its length and width are both decreased by 2 cm its area is decreased by 108 cm. squared. find its original dimensions. <BR>\n" );
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document.write( "Let the width be \"x\" cm.<BR>\n" );
document.write( "Then the length is \"x+12\" cm<BR>\n" );
document.write( "And the area = x(x+12) = x^2+12x cm^2<BR>\n" );
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document.write( "Change the dimensions:<BR>\n" );
document.write( "width = \"x-2\" cm<BR>\n" );
document.write( "length = \"x+10\" cm<BR>\n" );
document.write( "New area = (x-2)(x+10) = x^2 + 8x - 20 cm^2<BR>\n" );
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document.write( "Equations :<BR>\n" );
document.write( "Old area - New area = 108 cm^2<BR>\n" );
document.write( "x^2+12x -(x^2 + 8x - 20) = 108<BR>\n" );
document.write( "4x + 20 = 108<BR>\n" );
document.write( "4x = 88<BR>\n" );
document.write( "x = 22 cm (original width)<BR>\n" );
document.write( "x+12 = 24 cm (original length)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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