document.write( "Question 179472: Will you please help. My thought process is to multiply the first equation by 3. That will cancel the problem out to 0. Please help! \r
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document.write( "Solve by substitution or elimination method: \r
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document.write( "4x-5y=14
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document.write( "-12x+15y=-42\r
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Algebra.Com's Answer #134411 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve by substitution or elimination method: \n" ); document.write( "4x-5y=14 \n" ); document.write( "-12x+15y=-42 \n" ); document.write( "--------------------- \n" ); document.write( "Multiply 1st by 3 to get: \n" ); document.write( "12x - 15y = 42 \n" ); document.write( "-12x+ 15y = -42 \n" ); document.write( "--------------------- \n" ); document.write( "Important thought: IF you assume the x's and the y's are respectively \n" ); document.write( "the same, you may add the two equations to get: \n" ); document.write( "0 = 0 \n" ); document.write( "---------------------- \n" ); document.write( "Now, 0=0 is a true statement. \n" ); document.write( "So, your assumption was correct; the x's and the y's are respectively the same. \n" ); document.write( "----------- \n" ); document.write( "So x may have any value; then y = (12/15)x - (42/15) \n" ); document.write( "------------------------------------------------------ \n" ); document.write( "What does that say about the SYSTEM of two equations? \n" ); document.write( "It says one is the multiple of the other; they are essentially the same. \n" ); document.write( "========================================================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |