document.write( "Question 179472: Will you please help. My thought process is to multiply the first equation by 3. That will cancel the problem out to 0. Please help! \r
\n" ); document.write( "\n" ); document.write( "Solve by substitution or elimination method: \r
\n" ); document.write( "\n" ); document.write( "4x-5y=14
\n" ); document.write( "-12x+15y=-42\r
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Algebra.Com's Answer #134411 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Solve by substitution or elimination method:
\n" ); document.write( "4x-5y=14
\n" ); document.write( "-12x+15y=-42
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\n" ); document.write( "Multiply 1st by 3 to get:
\n" ); document.write( "12x - 15y = 42
\n" ); document.write( "-12x+ 15y = -42
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\n" ); document.write( "Important thought: IF you assume the x's and the y's are respectively
\n" ); document.write( "the same, you may add the two equations to get:
\n" ); document.write( "0 = 0
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\n" ); document.write( "Now, 0=0 is a true statement.
\n" ); document.write( "So, your assumption was correct; the x's and the y's are respectively the same.
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\n" ); document.write( "So x may have any value; then y = (12/15)x - (42/15)
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\n" ); document.write( "What does that say about the SYSTEM of two equations?
\n" ); document.write( "It says one is the multiple of the other; they are essentially the same.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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