document.write( "Question 179445: I hate fractions. I think I understand absolute value enough but when you throw fractions into the mix I get confused. This problem also has 2 fractions so im real confused.\r
\n" ); document.write( "\n" ); document.write( "this is the problem |x-1/3|=|1/2x+1/6|\r
\n" ); document.write( "\n" ); document.write( "x-1/3=1/2x+1/6
\n" ); document.write( " First I subtract 1/3 from each side to get
\n" ); document.write( "x=1/2x+1/9
\n" ); document.write( " then I subtract the 1/2x from both sides to get
\n" ); document.write( "1/2x=1/9
\n" ); document.write( " this is where i get confused. if i divide by the 1/2 i get 2/9. but my books says the answer is 1 ----so where did i go wrong. I know there is another side to the problem still,but if I cant get the first half then??????
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Algebra.Com's Answer #134379 by MissionPossible(18)\"\" \"About 
You can put this solution on YOUR website!
You made the mistake.
\n" ); document.write( "this is the problem |x-1/3|=|1/2x+1/6|
\n" ); document.write( "x-1/3=1/2x+1/6 ------>This is wrong.
\n" ); document.write( "You can not just pull it out from the absolute
\n" ); document.write( "The theory is If |A|=|B| Then ---> A^2 = B^2
\n" ); document.write( "|x-1/3|=|1/2x+1/6| -----> (x-1/3)^2 = (1/2x+1/6)^2
\n" ); document.write( "(x-1/3)^2 = (1/2x+1/6)^2
\n" ); document.write( "x^2 -(2/3)x + (1/9) = (1/4)x^2 +(1/6)x + (1/36)-------(1)
\n" ); document.write( "36 * Eq(1)
\n" ); document.write( "36x^2 - 24x + 4 = 9x^2 + 6x + 1
\n" ); document.write( "27x^2 - 30x + 3 = 0
\n" ); document.write( "divide by 3
\n" ); document.write( "9x^2 - 10x + 1 = 0
\n" ); document.write( "(9x -1 )(x-1) = 0
\n" ); document.write( "Then x = 1/9 , 1 Ans.\r
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