document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=179433>Question 179433</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the system 4x-5y=4 amd 8x-5y=-5 is to be solved using the addition by what constant should one of the equations be multipled if the x terms are to drop out?\r<BR>\n" );
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document.write( "a) 1/2<BR>\n" );
document.write( "b) 4<BR>\n" );
document.write( "c) -2<BR>\n" );
document.write( "d) -4 \r<BR>\n" );
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document.write( "explain your answer </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #134363 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=134363\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Notice how the x coefficients are 4 and 8. So the LCM is 8 (since they both go into 8). The goal is to make the coefficients equal but opposite. So this means that we want -8 and 8 (so they add to 0). This means that you multiply 4 by -2 to get -8.\r<BR>\n" );
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document.write( "So the answer is C) -2 </SPAN>\n" );
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