document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=179429>Question 179429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A= 2prh + 2pr(sqaured) this is the formula for the surface area of circular cylinder. i want to know the height.  p stands for pie/ the r is squared in the second half of the problem\r<BR>\n" );
document.write( "\n" );
document.write( "i got to A-2pr squared = 2prh\r<BR>\n" );
document.write( "\n" );
document.write( "when i divided by 2pr i dont understand why you get h= A/2pr - r \r<BR>\n" );
document.write( "\n" );
document.write( "wouldn't the 2pr cancel each other out. please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #134359 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=134359\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A= 2prh + 2pr(sqaured) this is the formula for the surface area of circular cylinder. i want to know the height.<BR>\n" );
document.write( "------<BR>\n" );
document.write( "2prh = A - 2pr^2\r<BR>\n" );
document.write( "\n" );
document.write( "h = [A-2pr^2] / [2pr]\r<BR>\n" );
document.write( "\n" );
document.write( "=========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "StanH. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );