document.write( "Question 179403: find the equation , in standard form, of the line perpendicular to 2x-3y=-5 and passing through(3, -2) \r
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document.write( "I do not know how to begin , please help \n" );
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Algebra.Com's Answer #134328 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! when lines are perpendicular they have slopes that are negative inverses of each other \n" ); document.write( ": \n" ); document.write( "so lets find the slope of our equation: \n" ); document.write( ": \n" ); document.write( "2x-3y=-5---->-3y=-2x-5--->y=(2/3)x+(5/3) \n" ); document.write( ": \n" ); document.write( "so our slope is 2/3. Therefore the line perpedicular to this line will have a slope of -3/2 \n" ); document.write( ": \n" ); document.write( "so we have a slope=m=-3/2 and we have a given point (3,-2,). So lets use the point slope formula which is y-k=m(x-h) where m is the slope and (h,k) is any point on the ine \n" ); document.write( ": \n" ); document.write( "y+2=(-3/2)(x-3) \n" ); document.write( ": \n" ); document.write( "2y+4=-3(x-3).......multiplied all terms by 2 to eliminate fraction \n" ); document.write( ": \n" ); document.write( "2y+4=-3x+9.....distributed right side \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "lets graph to see if these are perpendicular \n" ); document.write( ": \n" ); document.write( " |