document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=179274>Question 179274</A>: <I><SPAN STYLE=\"word-break: break-all;\"> #1. In a class, there are 20 men and 15 women. Find the ratio of the number of men to the number of students in the class. Express the ratio as a fraction reduced to the lowest term.\r<BR>\n" );
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document.write( "2. Determine whether each of the ordered pair is a solution of,<BR>\n" );
document.write( "3x-4y>7:  (0,0), (3,-6), (-2,-5), -3,4)\r<BR>\n" );
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document.write( "#3 A chemist needs to mix a 40% acid solution with 70% acid solution to obtain the 12 litters of 50%acid solution. How many liters of each of the acid solutions must be used?\r<BR>\n" );
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document.write( "#4. Solve the proportion:45/2=360/x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #134291 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=134291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In a class, there are 20 men and 15 women. Find the ratio of the number of men to the number of students in the class. Express the ratio as a fraction reduced to the lowest term.<BR>\n" );
document.write( "men:women = 20:15 = 4:3<BR>\n" );
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document.write( "2. Determine whether each of the ordered pair is a solution of,<BR>\n" );
document.write( "3x-4y>7: (0,0), (3,-6), (-2,-5), (-3,4)<BR>\n" );
document.write( "(0,0): 0-0 > 7 false<BR>\n" );
document.write( "(3,-6): 9-24 > 7 false<BR>\n" );
document.write( "(-2,-5): -6 + 20 > 7 true<BR>\n" );
document.write( "(-3,4): -9 -16 > 7 false<BR>\n" );
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document.write( "#3 A chemist needs to mix a 40% acid solution with 70% acid solution to obtain the 12 liters of 50% acid solution. How many liters of each of the acid solutions must be used? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.40x + 0.70(12-x) = 0.50*12<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "40x + 70*12 -70x = 50*12<BR>\n" );
document.write( "-30x = -20*12<BR>\n" );
document.write( "x = 8 liters (amt. of 40% solution in the mixture)<BR>\n" );
document.write( "12-8 = 4 liters (amt. of 70% solution in the mixture)<BR>\n" );
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document.write( "#4. Solve the proportion:45/2=360/x<BR>\n" );
document.write( "Cross-multiply<BR>\n" );
document.write( "45x = 2*360<BR>\n" );
document.write( "x = 16<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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