document.write( "Question 179370This question is from textbook algebra structure and method
\n" ); document.write( ": can you please help me solve by completing the square of: (((2x^2-3x+1=0))) \n" ); document.write( "

Algebra.Com's Answer #134288 by Mathtut(3670) $\"\"$ $\"About$

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$\"%282x%5E2-3x%29%2B1=0\"$
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\n" ); document.write( " $\"2%28x%5E2-%283%2F2%29x%29%2B1=0\"$ factored a two out of the x terms
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\n" ); document.write( " $\"2%28x%5E2-%283%2F2%29x%2B%289%2F16%29%29%2B1-%289%2F16%29=0\"$ took coefficient in front of x term and divided by 2.(3/2)/2= 3/4. Then we square that value $\"%283%2F4%29%5E2\"$ =9/16 which is the value you add to complete the square , but then you have to subtract it back out, outside the parenthesis to keep and equivilent equation
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\n" ); document.write( " $\"2%28x-%283%2F4%29%29%5E2%2B%287%2F16%29=0\"$ \n" ); document.write( "

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