document.write( "Question 179296: Solve the equation :(8/(x+1))-(5/2)=(4/(3x+3))\r
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\n" ); document.write( "\n" ); document.write( "I need help solving this problem for x. I know I multiply the denominators by 6(x+1) but after that I am not sure what to do. Any help with this problem will be greatly appreciated. Thank you
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Algebra.Com's Answer #134231 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Solve the equation :(8/(x+1))-(5/2)=(4/(3x+3))
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\n" ); document.write( "I need help solving this problem for x. I know I multiply the denominators by 6(x+1) but after that I am not sure what to do. Any help with this problem will be greatly appreciated. Thank you\r
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\n" ); document.write( "\n" ); document.write( "YOU MULTIPLY THE NUMERATORS BY 6(x+1)BECAUSE 6(x+1) IS THE LOWEST COMMON DENOMINATOR. THIS WILL GET RID OF THE FRACTIONS:\r
\n" ); document.write( "\n" ); document.write( "8/(x+1))-(5/2)=(4/(3x+3)) and this equals 8/(x+1))-(5/2)=(4/3(x+1))
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\n" ); document.write( "\"48-15%28x%2B1%29=8\"=
\n" ); document.write( "\"48-15x-15=8\" =
\n" ); document.write( "\"33-15x=8\"subtract 33 from each side
\n" ); document.write( "\"-15x=-25\"
\n" ); document.write( "\"x=25%2F15=5%2F3\" or one and two thirds----------------ans\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "\"8%2F%28%285%2F3%29%2B1%29-5%2F2=4%2F%283%2A%285%2F3%29%2B3%29\"=
\n" ); document.write( "\"8%2F%288%2F3%29-5%2F2=4%2F8\"=
\n" ); document.write( "\"3-5%2F2=1%2F2\"=
\n" ); document.write( "\"6%2F2-5%2F2=1%2F2\"
\n" ); document.write( "\"1%2F2=1%2F2\"\r
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r
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