document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=179299>Question 179299</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of 4 times Joan's age and 3 times Jim's age is 47. Jim is 1 year less than twice as old as Joan. Find their ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #134228 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=134228\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=Joan's age; 4 times Joan's age=4x<BR>\n" );
document.write( "Then 2x-1=Jim's age; 3 times Jim's age=3(2x-1)=6x-3\r<BR>\n" );
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document.write( "Now we are told that:<BR>\n" );
document.write( "4x+6x-3=47  add 3 to each side<BR>\n" );
document.write( "4x+6x-3+3=47+3  collect like terms<BR>\n" );
document.write( "10x=50 divide each side by 10<BR>\n" );
document.write( "x=5--------------------------------Joan's age<BR>\n" );
document.write( "2x-1=2*5-1=9-----------------------Jim's age\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "4*5 +3*9=47<BR>\n" );
document.write( "20+27=47<BR>\n" );
document.write( "47=47\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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