document.write( "Question 179315This question is from textbook Merrill Algebra 1
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document.write( ": I am confused about this question. In the book it says that the average is not 50 miles per hour. I need to know how to set up the problem to solve it:
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document.write( "Joan Bidney travels from Cincinnati to Winston-Salem at an average rate of 40 miles per hour and returns at an average rate of 60 miles per hour. What is her average speed for the trip? (Hint: the average speed is not 50 miles per hour.) \n" );
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Algebra.Com's Answer #134224 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! ok, lets call the distance d, the rate r, and the time t \n" ); document.write( ": \n" ); document.write( "d=40t.....trip to \n" ); document.write( "d=60t.....trip back \n" ); document.write( ": \n" ); document.write( "solve for t \n" ); document.write( ": \n" ); document.write( "t=d/40....trip to \n" ); document.write( "t=d/60....trip back \n" ); document.write( ": \n" ); document.write( "now lets take the time traveled for the entire to and back trip and multiply it by average rate for the whole trip which will be equal to 2d \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " |