document.write( "Question 179309: I am looking for a non-profit tutor. I am having problems understanding the process of solving this problem. The question is the squareroot of (x+2) minus x equals 0. I am solving for x. Can someone please explain. I keep coming up with 0 and I am not sure.
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Algebra.Com's Answer #134214 by Mathtut(3670)\"\" \"About 
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\"sqrt%28x%2B2%29-x=0\"
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\n" ); document.write( "\"sqrt%28x%2B2%29=x\"added x to both sides
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\n" ); document.write( "\"x%2B2=x%5E2\"squared both sides
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\n" ); document.write( "\"x%5E2-x-2=0\"put all terms on 1 side
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\n" ); document.write( "\"%28x-2%29%28x%2B1%29=0\"factored
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\n" ); document.write( "x=2 and x=-1
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\n" ); document.write( "check for extraneous roots
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\n" ); document.write( "-1 is and extraneous root so we throw it out(it does not make the statement true
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