document.write( "Question 25001: Separate 800 into three parts, such that the sum of the first, 1/2 of the second, and 2/5 of the third is 400; and the sum of the second, 3/4 of the first, and 1/4 of the third is 400. \n" ); document.write( "
Algebra.Com's Answer #13413 by quentin252(19)![]() ![]() ![]() You can put this solution on YOUR website! alright... \n" ); document.write( "3 equations , 3 variables\r \n" ); document.write( "\n" ); document.write( "1. x+y+z=800 \n" ); document.write( "2. x+(1/2)y+(2/5)z=400 \n" ); document.write( "3. y+(3/4)x+(1/4)z=400\r \n" ); document.write( "\n" ); document.write( "1. x=800-y-z \n" ); document.write( "2. (800-y-z)+(1/2)y+(2/5)z=400 \n" ); document.write( " -> 400 - (1/2)y - (3/5)z = 0 \n" ); document.write( " -> y = (400 -(3/5)z)*2 = 800 - (6/5)z \n" ); document.write( "3. (800 - (6/5)z) + (3/4)(800-(800-(6/5)z)-z)) + (1/4)z = 400 \n" ); document.write( " -> 800 - (6/5)z + (3/4)(800-800+(6/5)z-z)+(1/4)z = 400 \n" ); document.write( " -> 400 - (6/5)z + (3/4)(1/5)z + (1/4)z = 0 \n" ); document.write( " -> 400 + (-6/5 + 3/20 + 1/4)z = 0 \n" ); document.write( " => 400 -(4/5)z = 0 -->> (4/5)z = 400 -->> z = 400*5/4 = 500 \n" ); document.write( " -> so y = 200 and so x = 100 \n" ); document.write( " |