document.write( "Question 179180This question is from textbook College Mathematics
\n" ); document.write( ": I am looking for the domain and the range for the equation: x^2+y = 10\r
\n" ); document.write( "\n" ); document.write( "I thought that the square root of a negative number was imaginary and, as such we could not have a function from this equation. Apparently, this is not correct. Can you please explain what are and how to find the domain and range here?
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Algebra.Com's Answer #134126 by Mathtut(3670)\"\" \"About 
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write this as y=-x^2+10
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\n" ); document.write( "\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C-x%5E2%2B10%29\"
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\n" ); document.write( "the domain (input values) x values in this case is all real numbers
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\n" ); document.write( "the range (output values) y values in this case is much more difficult to determine normally.
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\n" ); document.write( "try solving for x: \"x%5E2=-y%2B10\" this doesnt always work but at times it does, and is a good starting point.
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\n" ); document.write( "x= + or -\"sqrt%28-y%2B10%29\" since we cant have a negative number inside the square root sign ,this does limit the range. -y+10 has to be greater than or equal to zero.
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\n" ); document.write( "\"-y%2B10%3E=0\"
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\n" ); document.write( "\"-y%3E=-10\"
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\n" ); document.write( "\"y%3C=10\"..........remember that when you divide or multiply an inequality by a negative number you need to reverse the sign.....
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\n" ); document.write( "so {y:y<=10} is the range...so all reals less than 10. y cannot for instance take on the value 12 otherwise you would have 12=-x^2+10
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\n" ); document.write( "2=-x^2
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\n" ); document.write( "x^2=-2...and we know that wont work...
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