document.write( "Question 179180This question is from textbook College Mathematics
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document.write( ": I am looking for the domain and the range for the equation: x^2+y = 10\r
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document.write( "I thought that the square root of a negative number was imaginary and, as such we could not have a function from this equation. Apparently, this is not correct. Can you please explain what are and how to find the domain and range here? \n" );
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Algebra.Com's Answer #134126 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! write this as y=-x^2+10 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "the domain (input values) x values in this case is all real numbers \n" ); document.write( ": \n" ); document.write( "the range (output values) y values in this case is much more difficult to determine normally. \n" ); document.write( ": \n" ); document.write( "try solving for x: \n" ); document.write( ": \n" ); document.write( "x= + or - \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "so {y:y<=10} is the range...so all reals less than 10. y cannot for instance take on the value 12 otherwise you would have 12=-x^2+10 \n" ); document.write( ": \n" ); document.write( "2=-x^2 \n" ); document.write( ": \n" ); document.write( "x^2=-2...and we know that wont work... \n" ); document.write( " |