document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=24908>Question 24908</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Business and finance.  In planning for a new item, a manufacturer assumes that the number of items produced x and the cost in dollars C of producing these items are related by a linear equation.  Projections are that 100 items will cost $10,000 to produce and that 300 items will cost $22,000 to produce.  Find the equation that relates C and x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13410 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13410\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have two points: (100,10000) and (300,22000)<BR>\n" );
document.write( "The equation of the relationship will be C=mx+b<BR>\n" );
document.write( "Find \"m\":  m = [22000-10000]/[300-100]= 12000/200= 60<BR>\n" );
document.write( "You now have x=100 when C=10000, and m=60<BR>\n" );
document.write( "Put those into the form C=mx+b to find \"b\".<BR>\n" );
document.write( "10000=60(100)+b<BR>\n" );
document.write( "10000=6000+b<BR>\n" );
document.write( "b=4000<BR>\n" );
document.write( "The equation you want is C=60x+4000\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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