document.write( "Question 25016: solve and graph 4 isless than 2x-2 is less than 10. \n" ); document.write( "
Algebra.Com's Answer #13408 by rapaljer(4671)\"\" \"About 
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Consider this a problem with three parts: the left part, the center part, and the right part. Whatever you do to one part, you must do to ALL three parts, in order to keep the inequality in balance.\r
\n" ); document.write( "\n" ); document.write( "4<2x-2 <10\r
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\n" ); document.write( "\n" ); document.write( "Start by adding +2 to the left, the middle, and the right.\r
\n" ); document.write( "\n" ); document.write( "4+2 <2x -2+2 <10+2
\n" ); document.write( "6<2x <12\r
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\n" ); document.write( "\n" ); document.write( "Next, to undo the 2 times the x, divide each part by 2:
\n" ); document.write( "\"6%2F2+%3C%282x%29%2F2+%3C12%2F2\"
\n" ); document.write( "\"3+%3C+x+%3C+6+\"\r
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\n" ); document.write( "\n" ); document.write( "To graph it, draw a numberline, locate the numbers 3 and 6 to the right of zero on the numberline, and shade all values between 3 and 6. You need to put either parentheses or open circles on the endpoints 3 and 6 to indicate that the endpoints are NOT included.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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