document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=179117>Question 179117</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve if it is an equation if not, simplify it. thank you.\r<BR>\n" );
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document.write( " 26)  (x + 3)^-1/3 = -1\r<BR>\n" );
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document.write( "24)  25^3/2  =  \r<BR>\n" );
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document.write( "(square root) 22)  x = SR(1-8x) + 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #134070 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=134070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 26) (x + 3)^-1/3 = -1<BR>\n" );
document.write( "Raise both sides to the -3 power to get:<BR>\n" );
document.write( "x+3 = -1<BR>\n" );
document.write( "x = -4<BR>\n" );
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document.write( "24) 25^3/2 = 5^3 = 125<BR>\n" );
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document.write( "22) x = SR(1-8x) + 2<BR>\n" );
document.write( "SR(1-8x) = x-2<BR>\n" );
document.write( "Square both sides to get:<BR>\n" );
document.write( "1-8x = x^2 -4x + 4<BR>\n" );
document.write( "x^2 + 4x  +3 = 0<BR>\n" );
document.write( "(x+1)(x+3) = 0<BR>\n" );
document.write( "x = -1 or x = -3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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