document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=179090>Question 179090</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following system by any method\r<BR>\n" );
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document.write( "x=5/4y+12<BR>\n" );
document.write( "4x-5y=12\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #134039 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=134039\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the following system by any method <BR>\n" );
document.write( "x=5/4y+12  (I think you mean 5/(4y), but it could be 5/(4y).<BR>\n" );
document.write( "4x-5y=12 <BR>\n" );
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document.write( "Since x is already shown in terms of y, sub for x into the 2nd eqn.<BR>\n" );
document.write( "4x-5y=12 <BR>\n" );
document.write( "4*((5y/4) + 12) -5y = 12<BR>\n" );
document.write( "5y +48 -5y = 12<BR>\n" );
document.write( "48 = 12<BR>\n" );
document.write( "These 2 eqns are inconsistent, so there is no solution.<BR>\n" );
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