document.write( "Question 179027: A dolphin can swim 30 miles per hour.
\n" ); document.write( "A sea lion can swim 25 miles per hour.If both animals swim for 5 hours, how much farther will the dolphin go?
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Algebra.Com's Answer #133981 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"d%5Bd%5D\"= the distance the dolphin travels in miles
\n" ); document.write( "Let \"d%5Bs%5D\"= the distance the sea lion travels in miles
\n" ); document.write( "Let \"r%5Bd%5D\"= the dophin's speed
\n" ); document.write( "Let \"r%5Bs%5D\"= the sea lion's speed
\n" ); document.write( "Let \"t%5Bd%5D\"= elapsed time for the dolphin
\n" ); document.write( "Let \"t%5Bs%5D\"= elapsed time for the sea lion
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\n" ); document.write( "I can write equations for both animals
\n" ); document.write( "\"d%5Bd%5D+=+r%5Bd%5D%2At%5Bd%5D\"
\n" ); document.write( "and
\n" ); document.write( "\"d%5Bs%5D+=+r%5Bs%5D%2At%5Bs%5D\"
\n" ); document.write( "-----------------------
\n" ); document.write( "given:
\n" ); document.write( "\"r%5Bd%5D=+30\"mi/hr
\n" ); document.write( "\"r%5Bs%5D+=25\"mi/hr
\n" ); document.write( "\"t%5Bd%5D+=+5\"hrs
\n" ); document.write( "\"t%5Bs%5D=+5\"hrs
\n" ); document.write( "------------------
\n" ); document.write( "Now I can write
\n" ); document.write( "\"d%5Bd%5D+=+30%2A5\"
\n" ); document.write( "\"d%5Bd%5D+=+150\"mi
\n" ); document.write( "\"d%5Bs%5D+=+25%2A5\"
\n" ); document.write( "\"d%5Bs%5D+=+125\"mi
\n" ); document.write( "\"150+-+125+=+25\"
\n" ); document.write( "The dolpin can swim 25 mi farther than the sea lion in 5 hrs
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