document.write( "Question 179028: I can't seem to solve both just one of them, where did I go wrong? Please help.
\n" ); document.write( "Solve by any method. I tried the addition method.
\n" ); document.write( "3x + 2y = -3
\n" ); document.write( "2x - 5y = 17\r
\n" ); document.write( "\n" ); document.write( "I solved for y but when I plugged back in to solve for x it did't work. Thanks.
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Algebra.Com's Answer #133977 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
multiply the first one by 2 and the second one by 3. then subtract them
\n" ); document.write( "\"3x+%2B+2y+=+-3\"
\n" ); document.write( "mult by 2 gives
\n" ); document.write( "\"6x+%2B+4y+=+-6\"\r
\n" ); document.write( "\n" ); document.write( "\"2x+-+5y+=+17\"
\n" ); document.write( "mult by 3
\n" ); document.write( "\"6x+-+15y+=+51\"\r
\n" ); document.write( "\n" ); document.write( "Now subtract one from the other
\n" ); document.write( "\"6x+%2B+4y+=+-6\"
\n" ); document.write( "\"6x+-+15y+=+51\"
\n" ); document.write( "-------------------
\n" ); document.write( "\"19y+=+-57\"
\n" ); document.write( "\"y+=+-3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Find x using the first equation and y=-3
\n" ); document.write( "\"3x+%2B+2%28-3%29+=+-3\"
\n" ); document.write( "\"3x+-6+=+-3+\"
\n" ); document.write( "\"3x+=+3\"
\n" ); document.write( "x=1\r
\n" ); document.write( "\n" ); document.write( "Now use both x = 1 and y = -3 in the second to verify
\n" ); document.write( "Does \"2%281%29+-5%28-3%29+=+17\"???
\n" ); document.write( "\"2+%2B+15+=+17\" so that works
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