document.write( "Question 178995: You invested $12,000, part of it in stock that paid 12% annual interest. However, the rest of the money suffered a 5% loss. If the annual income from both investments was $620, how much was invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #133937 by Mathtut(3670) $\"\"$ $\"About$

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let x and y be the amount invested in each rate
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\n" ); document.write( "x+y=12000.......eq 1
\n" ); document.write( ".12x-.05y=620...eq 2
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\n" ); document.write( "rewrite eq 1 to x=12000-y and plug that value into eq 2
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\n" ); document.write( ".12(12000-y)-.05y=620
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\n" ); document.write( "1440-.12y-.05y=620
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\n" ); document.write( "-.17y=-820
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\n" ); document.write( " $\"highlight%28y=4823.53%29\"$ amount invested in the 5% loss
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\n" ); document.write( " $\"highlight%28x=12000-4823.53=7176.47%29\"$ amount invested in 12% investment \n" ); document.write( "

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