document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=24900>Question 24900</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of the line L satisfying the given geometric conditions.\r<BR>\n" );
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document.write( "the first one is -  L has y-intercept (0, -3) and is parallel to the line with equation y=2/3x + 1.\r<BR>\n" );
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document.write( "the second one is - L has y-intercept (0,2) and is perpendicular to the line with equation 2x-3y=6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13391 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13391\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first line has the SAME slope as y = 2/3x + 1, which is m = 2/3.  If its y intercept is -3, then the equation must be <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%282%2F3%29x+-+3 ALIGN=MIDDLE  ALT=\"y+=+%282%2F3%29x+-+3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The second line must be perpendicular to 2x - 3y = 6.  You have to solve for y in order to find the slope:<BR>\n" );
document.write( "2x-3y = 6<BR>\n" );
document.write( "-3y = -2x + 6\r<BR>\n" );
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document.write( "Divide both sides by -3:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=%28-2x%29%2F%28-3%29+%2B+6%2F%28-3%29 ALIGN=MIDDLE  ALT=\"y+=%28-2x%29%2F%28-3%29+%2B+6%2F%28-3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%282%2F3%29x+-2 ALIGN=MIDDLE  ALT=\"y+=+%282%2F3%29x+-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so the slope of this line is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "The slope of a line PERPENDICULAR to this line is the NEGATIVE RECIPROCAL of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >, which is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3%2F2 ALIGN=MIDDLE  ALT=\"-3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  If the line has a y intercept of 2, then the equation of the line is <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%28-3%2F2%29x%2B+2 ALIGN=MIDDLE  ALT=\"y+=+%28-3%2F2%29x%2B+2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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