document.write( "Question 178966: I need help please with this graphing problem by solving each system by addition\r
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document.write( "x-2y=-1
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document.write( "-x+5y=9 \n" );
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Algebra.Com's Answer #133907 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! x-2y=-1.....eq 1 \n" ); document.write( "-x+5y=9.....eq 2 \n" ); document.write( ": \n" ); document.write( "what you doing here is adding all the terms from eq1 to all the terms in eq 2 \n" ); document.write( ": \n" ); document.write( "we can only put together like terms so x-x=0...so the x term is eliminated \n" ); document.write( ": \n" ); document.write( "-2y+5y=3y \n" ); document.write( "-1+9=8 \n" ); document.write( ": \n" ); document.write( "so we are left with 3y=8 \n" ); document.write( ": \n" ); document.write( "3y=8 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "now take y's found value and plug it back into either numbered equation \n" ); document.write( "I choose eq 1 \n" ); document.write( ": \n" ); document.write( "x-2(8/3)=-1 \n" ); document.write( ": \n" ); document.write( "x-16/3=-1 \n" ); document.write( ": \n" ); document.write( "3x-16=-3.....multiplied all terms by 3 \n" ); document.write( ": \n" ); document.write( "3x=13 \n" ); document.write( ": \n" ); document.write( " |