document.write( "Question 178877: A motorcycle breaks down and the rider has to walk the rest of the way to work. The motorcycle was traveling at 45mi/h, and the rider walks at a speed of 6 mi/h. The distance from home to work is 25 miles, and the total time for the trip was 2 hours. How far did the motorcycle go before it broke down? \n" ); document.write( "

Algebra.Com's Answer #133843 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"t\"$ = the time on the motorcycle
\n" ); document.write( "Let $\"d\"$ = the distance travelled on the motorcycle
\n" ); document.write( " $\"d%2F45+%2B+%2825+-+d%29%2F6+=+2\"$
\n" ); document.write( "Multiply both sides by $\"90\"$
\n" ); document.write( " $\"2d+%2B+15%2A%2825+-+d%29+=+180\"$
\n" ); document.write( " $\"2d+%2B+375+-+15d+=+180\"$
\n" ); document.write( " $\"13d+=+375+-+180\"$
\n" ); document.write( " $\"13d+=+195\"$
\n" ); document.write( " $\"d+=+15\"$
\n" ); document.write( "The motorcycle went 15 mi before it broke down
\n" ); document.write( "check:
\n" ); document.write( " $\"d%2F45+%2B+%2825+-+d%29%2F6+=+2\"$
\n" ); document.write( " $\"15%2F45+%2B+%2825+-+15%29%2F6+=+2\"$
\n" ); document.write( " $\"15%2F45+%2B+10%2F6+=+2\"$
\n" ); document.write( " $\"2%2A15+%2B+10%2A15+=+2%2A90\"$
\n" ); document.write( " $\"30+%2B+150+=+180\"$
\n" ); document.write( " $\"180+=+180\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );