document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=178871>Question 178871</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bacteria culture doubles in size every 8 hrs.  The culture starts with 150 cells.  How many will there be after 24 hrs? 72hrs? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #133812 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=133812\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A bacteria culture doubles in size every 8 hrs. The culture starts with 150 cells. How many will there be after 24 hrs? 72hrs?<BR>\n" );
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document.write( "A(t) = A(0)*2^(t/8)<BR>\n" );
document.write( "A(24) = 150*2^(24/8) = 150*2^3 = 150*8 = 1200<BR>\n" );
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document.write( "A(72) = 150*2^(72/8) = 150*2^9 = 76800<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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