document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=178858>Question 178858</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One turkey weighs 3 pounds less than twice another.  If the heavier turkey weights 29 pounds, how much does the lighter turkey weigh? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #133804 by </B><A HREF=/tutors/aboutme.mpl?userid=EMStelley><B>EMStelley(208)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=EMStelley><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=EMStelley><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=133804\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call the other turkey's weight w.  Then \"one turkey weighs 3 pounds less than twice another\" is like saying that turkey weighs 2w-3.  The assumption has to be made that the heavier turkey is 2w-3, so<BR>\n" );
document.write( "2w-3=29<BR>\n" );
document.write( "2w=32<BR>\n" );
document.write( "w=16 </SPAN>\n" );
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