document.write( "Question 178845: a sign has a area of 60ft squared. if the width of is 4 ft shorter then the length, what are the dimensions of the sighn? \n" ); document.write( "
Algebra.Com's Answer #133800 by ankor@dixie-net.com(22740)\"\" \"About 
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a sign has a area of 60ft squared. if the width of is 4 ft shorter then the length, what are the dimensions of the sign?
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\n" ); document.write( "let x = width of the sign
\n" ); document.write( "then
\n" ); document.write( "(x+4) = length of the sign
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\n" ); document.write( "W * L = area
\n" ); document.write( "x(x+4) = 60
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\n" ); document.write( "x^2 + 4x = 60
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\n" ); document.write( "x^2 + 4x - 60 = 0; a quadratic equation
\n" ); document.write( "Factor this to:
\n" ); document.write( "(x+10)(x-6) = 0
\n" ); document.write( "positive solution is what we want here
\n" ); document.write( "x = 6 ft is the width
\n" ); document.write( "then
\n" ); document.write( "6 + 4 = 10 ft is the length
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\n" ); document.write( "Check solution by finding the area: 10 * 6 = 60 sq/ft
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