document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=178720>Question 178720</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you write the series in sigma notation?<BR>\n" );
document.write( "5,8,11,14,...,38?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #133702 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=133702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sum%283n%2B2%2Cn=1%2Cm%29 ALIGN=MIDDLE  ALT=\"sum%283n%2B2%2Cn=1%2Cm%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > where n is the natural numbers and m is the mth term in the sequence.  m can be calculated by taking the number of the mth term, subtracting 2 and dividing by 3(for instance take (38-2)/3=12)...so m would be 12 in that case.  Generally when adding terms in a sequence you will be given m.<BR>\n" );
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