document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=178702>Question 178702</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given that z=3y+2/y-1, express y in terms of z<BR>\n" );
document.write( "and hence find the value of y when z=1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #133699 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=133699\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given that z=3y+2/y-1, express y in terms of z<BR>\n" );
document.write( "and hence find the value of y when z=1/2<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "z=(3y+2)/(y-1)<BR>\n" );
document.write( "zy - z = 3y + 2<BR>\n" );
document.write( "zy-3y = 2+z<BR>\n" );
document.write( "y(z-3) = z + 2<BR>\n" );
document.write( "y = (z+2)(z-3)<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "Let z = 1/2<BR>\n" );
document.write( "y = (5/2)/(-5/2)<BR>\n" );
document.write( "y = -1<BR>\n" );
document.write( "================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );