document.write( "Question 178718: Solve the following by substitution\r
\n" ); document.write( "\n" ); document.write( "2x-y=10
\n" ); document.write( "x=-2y
\n" ); document.write( "

Algebra.Com's Answer #133682 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"2x-y=10\", EQN 1
\n" ); document.write( "\"x=-2y\", EQN 2
\n" ); document.write( "Subst. EQN 2 in EQN 1:
\n" ); document.write( "\"2%28-2y%29-y=10\"
\n" ); document.write( "\"-4y-y=10\"
\n" ); document.write( "\"-5y=10\"--------->\"cross%28-5%29y%2Fcross%28-5%29=cross%2810%292%2Fcross%28-5%29\"
\n" ); document.write( "\"highlight%28y=-2%29\", subst. in EQn 2:
\n" ); document.write( "\"x=-2%28-2%29=highlight%284=x%29\"
\n" ); document.write( "Check via EQN 1:
\n" ); document.write( "\"2%284%29-%28-2%29=10\"
\n" ); document.write( "\"8%2B2=10\"
\n" ); document.write( "\"10=10\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
\n" ); document.write( "
\n" );