document.write( "Question 178686: please help me solve.
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Algebra.Com's Answer #133649 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "That has three sides. We solve for x in the middle side:\r\n" );
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document.write( "   -7 < 3 - 2x < 13\r\n" );
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document.write( "Add -3 to all three sides to cancel\r\n" );
document.write( "away the 3 in the middle\r\n" );
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document.write( "   -7 < 3 - 2x < 13\r\n" );
document.write( "   -3  -3        -3 \r\n" );
document.write( "  ------------------\r\n" );
document.write( "  -10 <   -2x  < 10\r\n" );
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document.write( "Now we divide all three sides by -2.\r\n" );
document.write( "But we must remember that when we divide\r\n" );
document.write( "by a negative number, the symbols reverse:\r\n" );
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document.write( "  -10      -2x     10\r\n" );
document.write( " ----- >  ----- > ---- \r\n" );
document.write( "  -2       -2      -2\r\n" );
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document.write( "    5  >    x   >  -5\r\n" );
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document.write( "And that is the same thing as\r\n" );
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document.write( "    -5 < x < 5\r\n" );
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document.write( "Sometimes that is written as (-5, 5),\r\n" );
document.write( "called \"interval notation\".\r\n" );
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document.write( "Edwin

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