document.write( "Question 24979: Please factor 6y4-486 \n" ); document.write( "

Algebra.Com's Answer #13364 by Earlsdon(6294) $\"\"$ $\"About$

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Factor:
\n" ); document.write( " $\"6y%5E4+-+486\"$ First, factor a 6.
\n" ); document.write( " $\"6%28y%5E4+-+81%29\"$ The parentheses contain the difference of two squares.
\n" ); document.write( " $\"6%28%28y%5E2%29%5E2+-+9%5E2%29\"$ This can be factored.
\n" ); document.write( " $\"6%28y%5E2+-+9%29%28y%5E2+%2B+9%29\"$ Now the $\"%28y%5E2+-+9%29\"$ is the difference of two squares and can be factored.
\n" ); document.write( " $\"6%28y+-+3%29%28y+%2B+3%29%28y%5E2+%2B+9%29\"$
\n" ); document.write( "Normally we would stop here, but if you are into complex binomials, you can go one step farther. $\"%28a%5E2+%2B+b%5E2%29\"$ will factor as $\"%28a+-+bi%29%28a+%2B+bi%29\"$ , so:
\n" ); document.write( " $\"6%28y+-+3%29%28y+%2B+3%29%28y+-+3i%29%28y+%2B+3i%29\"$ would be the complete factorisation. \n" ); document.write( "

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