document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=178637>Question 178637</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for X:    6x-7(x^1/2)- 3=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #133607 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=133607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for X: 6x-7(x^1/2)- 3=0<BR>\n" );
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document.write( "Rearrange:<BR>\n" );
document.write( "6x - 9sqrt(x) + 2sqrt(x) - 3 = 0\r<BR>\n" );
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document.write( "Factor to get:<BR>\n" );
document.write( "3sqrt(x)(2sqrt(x) - 3)+(2sqrt(x) - 3) = 0\r<BR>\n" );
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document.write( "Factor again to get:<BR>\n" );
document.write( "(2sqrt(x)-3)(3sqrt(x) + 1) = 0<BR>\n" );
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document.write( "sqrt(x) = 3/2 or sqrt(x) = -1/3<BR>\n" );
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document.write( "x = 9/4 or x = 1/9<BR>\n" );
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document.write( "Check the answers to see if either is extraneous.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );