document.write( "Question 178606This question is from textbook algebra 1
\n" ); document.write( ": How do i solve 3x-6y=30 and how do i solve y=-6x+34 using the expressions involving variables, substitution? \n" ); document.write( "
Algebra.Com's Answer #133567 by stanbon(75887)\"\" \"About 
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\n" ); document.write( "How do i solve
\n" ); document.write( "3x-6y=30
\n" ); document.write( "y=-6x+34
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\n" ); document.write( "Modify to get:
\n" ); document.write( "x - 2y = 10
\n" ); document.write( "y = -6x + 34
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\n" ); document.write( "Substitute to solve for \"y\":\r
\n" ); document.write( "\n" ); document.write( "y = -6(2y+10) + 34\r
\n" ); document.write( "\n" ); document.write( "y = -12y - 60 + 34
\n" ); document.write( "13y = -26
\n" ); document.write( "y = -2
\n" ); document.write( "-------------
\n" ); document.write( "Substitute to solve for \"x\":
\n" ); document.write( "x -2*-2 = 10
\n" ); document.write( "x = 6
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\n" ); document.write( "Ans: x = 6 and y = =2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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