document.write( "Question 178568: A merchant blends tea that sells for $3.45 a pound with tea that sells for $2.15 a pound to produce 80 pounds of a mixture that sells for $2.75 a pound.
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document.write( "How many pounds of the $3.45/lbs of tea does the new mixture contain? And how many pounds of the $2.15/lbs of tea does the new mixture contain? \n" );
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Algebra.Com's Answer #133541 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! let x and y be the amount of tea that sells fo 3.45 and 2.15 a pound respectively \n" ); document.write( ": \n" ); document.write( "x+y=80....................eq 1 \n" ); document.write( "3.45x+2.15y=2.75(80)......eq 2 \n" ); document.write( ": \n" ); document.write( "rewrite eq 1 to x=80-y and plug that value into eq 2 \n" ); document.write( ": \n" ); document.write( "3.45(80-y)+2.15y=2.75(80) \n" ); document.write( ": \n" ); document.write( "276-3.45y+2.15y=220 \n" ); document.write( ": \n" ); document.write( "-1.3y=56 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " |