document.write( "Question 178568: A merchant blends tea that sells for $3.45 a pound with tea that sells for $2.15 a pound to produce 80 pounds of a mixture that sells for $2.75 a pound.
\n" ); document.write( "How many pounds of the $3.45/lbs of tea does the new mixture contain? And how many pounds of the $2.15/lbs of tea does the new mixture contain?
\n" ); document.write( "

Algebra.Com's Answer #133541 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
let x and y be the amount of tea that sells fo 3.45 and 2.15 a pound respectively
\n" ); document.write( ":
\n" ); document.write( "x+y=80....................eq 1
\n" ); document.write( "3.45x+2.15y=2.75(80)......eq 2
\n" ); document.write( ":
\n" ); document.write( "rewrite eq 1 to x=80-y and plug that value into eq 2
\n" ); document.write( ":
\n" ); document.write( "3.45(80-y)+2.15y=2.75(80)
\n" ); document.write( ":
\n" ); document.write( "276-3.45y+2.15y=220
\n" ); document.write( ":
\n" ); document.write( "-1.3y=56
\n" ); document.write( ":
\n" ); document.write( "\"highlight%28y=43.07%29\"pounds of $2.15 tea
\n" ); document.write( ":
\n" ); document.write( "\"highlight%28x=80-43.07=36.93%29\"pounds of $3.45 tea
\n" ); document.write( "
\n" );