document.write( "Question 178565: what quantity x of an 80% solution must be added to a 15% solution to produce 600mL of a 40% solution \n" ); document.write( "
Algebra.Com's Answer #133521 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! \n" ); document.write( "what quantity x of an 80% solution must be added to a 15% solution to produce 600mL of a 40% solution \n" ); document.write( ": \n" ); document.write( "mix x amt with (600-x) amt \n" ); document.write( ": \n" ); document.write( ".8x + .15(600-x) = .4(600) \n" ); document.write( ".8x + 90 - .15x = 240 \n" ); document.write( ".8x - .15x = 240 - 90 \n" ); document.write( ".65x = 150 \n" ); document.write( "x = \n" ); document.write( "x = 230.77 ml of 80% solution \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution: (600 - 230.77 = 369.23 ml of 15% solution: \n" ); document.write( ".8(230.77) + .15(369.23) = .4(600) \n" ); document.write( " 184.62 + 55.38 = 240 \n" ); document.write( " |