document.write( "Question 24972: I rcvd an answer to this problem earlier (24882) but the steps and the reason why are still not clear to me. This was not taught to us as a formula, but just as a regular equation. So I am not sure why you would reverse the fraction instead of multiplying everything by 5 to remove the fraction
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\n" ); document.write( "\n" ); document.write( "F=9/5c+32, solve for C \n" ); document.write( "

Algebra.Com's Answer #13350 by AnlytcPhil(1806) $\"\"$ $\"About$

You can put this solution on YOUR website!

I rcvd an answer to this problem earlier (24882) but the steps and the reason\r\n" );
document.write( "why are still not clear to me. This was not taught to us as a formula, but just\r\n" );
document.write( "as a regular equation. So I am not sure why you would reverse the fraction\r\n" );
document.write( "instead of multiplying everything by 5 to remove the fraction\r\n" );
document.write( "HELP!!! \r\n" );
document.write( "F=9/5c+32, solve for C\r\n" );
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document.write( "You can multiply everything by 5\r\n" );
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document.write( "F = 9/5C + 32\r\n" );
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document.write( "5F = 9C + 160\r\n" );
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document.write( "5F - 160 = 9C\r\n" );
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document.write( "Factor out 5 on the left\r\n" );
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document.write( "5(F - 32) = 9C\r\n" );
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document.write( "Divide both sides by 9\r\n" );
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document.write( "5/9(F - 32) = C\r\n" );
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document.write( "or\r\n" );
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document.write( "C = 5/9(F - 32)\r\n" );
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document.write( "Edwin\r\n" );
document.write( "AnlytcPhil@aol.com

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