document.write( "Question 178530: Stan and Hilda can mow the lawn in 60 mins. if they work together. If hilda works twice as fast as Stan, how long does it take Stan to mow the lawn alone? \n" ); document.write( "
Algebra.Com's Answer #133488 by stanbon(75887)\"\" \"About 
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Stan and Hilda can mow the lawn in 60 mins. if they work together. If hilda works twice as fast as Stan, how long does it take Stan to mow the lawn alone?
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\n" ); document.write( "Together DATA:
\n" ); document.write( "time = 60 min/job ; rate = 1/60 job/min
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\n" ); document.write( "Hilda DATA:
\n" ); document.write( "time = x min/job ; rate = 1/x job/min
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\n" ); document.write( "Stan DATA:
\n" ); document.write( "time = 2x min/job; rate = 1/2x job/min
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\n" ); document.write( "Equation:
\n" ); document.write( "rate + rate = together rate
\n" ); document.write( "1/x + 1/2x = 1/60
\n" ); document.write( "60 + 30 = x
\n" ); document.write( "x = 90 min
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\n" ); document.write( "Stan time = 2x = 180 min or 3 hrs.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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