document.write( "Question 178522: How do you find the sum of the finite arithmetic series of 9, 16, 23, 30, ..., 100?\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #133475 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! I think I finally figured this one out.\r \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( "9 is added to each progressive term and 7's increased by the summation of the number of terms in the sequence The 7's part of this sequence is just a play on Gauss's summation formula. \n" ); document.write( ": \n" ); document.write( "so \n" ); document.write( ": \n" ); document.write( "9(n+1)+7n(n+1)/2. n is the number of terms . You can figure the number of terms by dividing whatever the number of the last term is and subtracting 9 ,then dividing by 7....such as 100 is the last term so subtract 9 and divide by 7...answer is 13......so n would equal 13 \n" ); document.write( ": \n" ); document.write( "9(13+1)+7(13)(14)/2=126+637= \n" ); document.write( ": \n" ); document.write( "you can rewrite the formula to \n" ); document.write( ": \n" ); document.write( "(n+1)(9+(7n/2))= \n" ); document.write( " \n" ); document.write( " |