document.write( "Question 178509: On a 255 mile trip gary traveled at an average of 70 mph, got a speeding ticket, and
\n" ); document.write( "then traveled at 60 mph for the remainder of the trip. If the entire trip took 4.5 hours and the speeding ticket stop took 30 minutes, how long did gary speed before he got stopped? \n" ); document.write( "
Algebra.Com's Answer #133456 by ankor@dixie-net.com(22740)\"\" \"About 
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On a 255 mile trip Gary traveled at an average of 70 mph, got a speeding ticket,
\n" ); document.write( " and then traveled at 60 mph for the remainder of the trip. If the entire trip
\n" ); document.write( " took 4.5 hours and the speeding ticket stop took 30 minutes, how long did Gary
\n" ); document.write( " speed before he got stopped?
\n" ); document.write( ":
\n" ); document.write( "Let t = time driven at 70 mph
\n" ); document.write( "The total driving time was 4 hrs, therefore:
\n" ); document.write( "(4-t) = time at 60 mph
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation; dist = speed * time
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\n" ); document.write( "Dist at 70 + dist at 60 = 255
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\n" ); document.write( "70t + 60(4-t) = 255
\n" ); document.write( ":
\n" ); document.write( "70t + 240 - 60t = 255
\n" ); document.write( ":
\n" ); document.write( "70t - 60t = 255 - 240
\n" ); document.write( ":
\n" ); document.write( "10t = 15
\n" ); document.write( "t = \"15%2F10\"
\n" ); document.write( "t = 1.5 hrs at 70 mph
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\n" ); document.write( "check solution (time at 60 mph: 4 - 1.5 = 2.5hrs)
\n" ); document.write( "1.5(70) + 2.5(60) =
\n" ); document.write( "105 + 150 = 255 mi confirms our solution \n" ); document.write( "
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