document.write( "Question 178493: The cost of 12 oranges and 7 apples is $5.36. 8 oranges and 5 apples cost $3.68. what is the cost of each orange? \n" ); document.write( "
Algebra.Com's Answer #133450 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
let the cost of each apple and orange be a and o respectively
\n" ); document.write( ":
\n" ); document.write( "7a+12o=5.36...eq 1
\n" ); document.write( "5a+8o=3.68....eq 2
\n" ); document.write( ":
\n" ); document.write( "use elimination method. muliply all terms in eq 1 by -5 and all terms in eq 2 by 7
\n" ); document.write( ":
\n" ); document.write( "-5(7a+12o=5.36--->-35a-60o=-26.8.....eq 1 revised
\n" ); document.write( "7(5a+8o=3.68------>35a+56o=25.76.....eq 2 revised
\n" ); document.write( ":
\n" ); document.write( "It is plain to see that the a terms are eliminated when you add these two equations together because -35a+35a=0. We are left with -60o+56o=-26.8+25.76
\n" ); document.write( ":
\n" ); document.write( "-4o=-1.04
\n" ); document.write( ":
\n" ); document.write( "\"highlight%28o=.26%29\"cents-cost of an orange
\n" ); document.write( ":
\n" ); document.write( "take o's found value and plug it back into any numbered equation
\n" ); document.write( ":
\n" ); document.write( "I choose eq 2
\n" ); document.write( ":
\n" ); document.write( "5a+8(.26)=3.68
\n" ); document.write( ":
\n" ); document.write( "5a+2.08=3.68
\n" ); document.write( ":
\n" ); document.write( "5a=1.60
\n" ); document.write( ":
\n" ); document.write( "\"highlight%28a=.32%29\"cents-cost of an apple\r
\n" ); document.write( "\n" ); document.write( ":
\n" ); document.write( " \n" ); document.write( "
\n" );