document.write( "Question 178499: 0.24(12)+0.06x=0.12(6+x)\r
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Algebra.Com's Answer #133434 by Mathtut(3670)\"\" \"About 
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0.24(12)+0.06x=0.12(6+x)
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\n" ); document.write( "distribute right side to .12(6+x)=.72+.12x and multiply out .24(12=2.88....so we then have
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\n" ); document.write( "2.88+.06x=.72+.12x
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\n" ); document.write( ".06x=2.16.......subtracted .06x and .72 from both sides
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