document.write( "Question 178427: I am in over my head here, so please use very simple explanations. Find b and c so that the parabola y=20x^2+bx+c has vertex (10,-3) \n" ); document.write( "
Algebra.Com's Answer #133395 by scott8148(6628)\"\" \"About 
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the vertex is on the axis of symmetry\r
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\n" ); document.write( "\n" ); document.write( "the general equation for the axis of symmetry is x = -b/(2a)\r
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\n" ); document.write( "\n" ); document.write( "in this case, 10=-b/(2*20)\r
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\n" ); document.write( "\n" ); document.write( "multiplying by 40 __ 400=-b __ -400=b\r
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\n" ); document.write( "\n" ); document.write( "the value of c can be found by substituting the vertex coordinates\r
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\n" ); document.write( "\n" ); document.write( "-3=20(10^2)-400(10)+c __ -3=2000-4000+c\r
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\n" ); document.write( "\n" ); document.write( "adding 2000 __ 1997=c
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