document.write( "Question 178427: I am in over my head here, so please use very simple explanations. Find b and c so that the parabola y=20x^2+bx+c has vertex (10,-3) \n" ); document.write( "
Algebra.Com's Answer #133395 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! the vertex is on the axis of symmetry\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the general equation for the axis of symmetry is x = -b/(2a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in this case, 10=-b/(2*20)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiplying by 40 __ 400=-b __ -400=b\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the value of c can be found by substituting the vertex coordinates\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-3=20(10^2)-400(10)+c __ -3=2000-4000+c\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "adding 2000 __ 1997=c \n" ); document.write( " |