document.write( "Question 24958: The sum of a number and its reciprocal is 25/12. What is the number? \n" ); document.write( "
Algebra.Com's Answer #13336 by Earlsdon(6294)\"\" \"About 
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Let n = the required number. You can write:
\n" ); document.write( "\"n+%2B+1%2Fn+=+25%2F12\" Simplify and solve for n.
\n" ); document.write( "\"%28n%5E2+%2B+1%29%2Fn+=+25%2F12\" Multiply both sides of the equation by n.
\n" ); document.write( "\"n%5E2+%2B+1+=+25n%2F12\" Multiply both sides by 12 and simplify.
\n" ); document.write( "\"12n%5E2+%2B+12+=+25n\" Subtract 25n from both sides.
\n" ); document.write( "\"12n%5E2+-+25n+%2B+12+=+0\" Solve for n by factoring.
\n" ); document.write( "\"%283n+-+4%29%284n+-+3%29+=+0\" Apply the zero products principle.
\n" ); document.write( "\"3n+-+4+=+0\" and/or \"4n+-+3+=+0\"
\n" ); document.write( "If \"3n+-+4+=+0\" then \"3n+=+4\" and \"n+=+4%2F3\"
\n" ); document.write( "If \"4n+-+3+=+0\" then \"4n+=+3\" and \"n+=+3%2F4\"\r
\n" ); document.write( "\n" ); document.write( "The answer is: There are two numbers that fit this situation.
\n" ); document.write( "\"4%2F3\" and \"3%2F4\" Check:\r
\n" ); document.write( "\n" ); document.write( "\"4%2F3+%2B+3%2F4+=+%2816+%2B+9%29%2F12\" = \"25%2F12\"
\n" ); document.write( "\"3%2F4+%2B+4%2F3+=+%289+%2B+16%29%2F12\" = \"25%2F12\"\r
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